找到数组轮转的X

问题：用C++代码实现函数 FindSortedArrayRotation。该函数接管一个整数数组和数组的长度。这个整数数组原来是有序的（升序），但被轮转了X位置（对给定的整数X (0 <= X <= (arrayLength – 1))，数组的每个元素向前移动X位置，也就是array[i]移动到array[(i+X)%arrayLength]。请实现FindSortedArrayRotation，找出X。要求时间必需小于O(n)

参考代码：

以下为引用的内容：

int FindSortedArrayRotation(int *array, int arrayLength)
{
　　// Insert your implementation here
　　/*　
After rotation the array was divided into 2 parts: array[0…x-1] and array[x…arrayLength-1]. And each part is sorted in ascending order. But array[x-1]>array[x]. This is a turn corner. My idea is use binary_search algorithm to find the turn corner.
Running time is O(log(2)).
*/
int left = 0;
int right = arrayLength – 1;
if(array[left]<= array[right]) return 0;
while(left<=right)
{
int middle = (left+right)/2;
if(array[middle -1] > array[middle]) return middle;
if(array[middle] > array[right]) left = middle + 1;
else right = middle -1;
}
return -1;
}