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JAVA函数实现任意给定一组数, 找出任意数相加之后的功效为35

2017-11-02 08:00 星期四 所属: JAVA 教程 浏览:48

用JAVA写一个函数。成果如下:任意给定一组数,譬喻{12,60,-8,99,15,35,17,18},找出任意数相加之后的功效为35(任意设定)的环境.

可以递归算法来解:

package test1;
    
import java.util.Arrays;
    
public class demo {
        
    public static void main(String[] args) {
        String str = "12,60,-8,99,15,35,17,18,8,10,11,12";
        int sum = 35;
        diguiSum(str,sum);
    }
        
    public static void diguiSum(String str,int sum) {
        String[] x = str.split(",");
        int[] array = arrayTransform(x);
        for (int i = 0; i < array.length; i++) {
            int[] cache = new int[i + 1];
            int ceng = -1;
            int cengQuit = i;
            int startPiont = 0;
            cir(ceng, cengQuit, startPiont, array, cache, sum);
        }
    }
    
    // 递归求功效
    public static void cir(int ceng, int cengQuit, int startPiont, int[] array, int[] cache, int sum) {
        ceng++;
        for (int i = startPiont; i < array.length; i++) {
            cache[ceng] = array[i];
            if (ceng == cengQuit) {
                if (getSum(cache) == sum) {
                    printcache(cache);
                }
                if (getSum(cache) > sum) {
                    break;
                }
            }
            if (ceng < cengQuit) {
                startPiont = i + 1;
                cir(ceng, cengQuit, startPiont, array, cache,sum);
            }
        }
    }
    
    // 获取组合数字之和
    public static int getSum(int[] cache) {
        int sum = 0;
        for (int i = 0; i < cache.length; i++) {
            sum = sum + cache[i];
        }
        return sum;
    }
    
    // 打印组合的大概
    public static void printcache(int[] cache) {
        for (int i = 0; i < cache.length; i++) {
            System.out.print(cache[i] + ",");
        }
        System.out.println();
    }
    
    // 转换数组范例 且为提高效率做筹备
    public static int[] arrayTransform(String[] strArray) {
        int length = 0;
    
        int[] array = new int[strArray.length];
        for (int i = 0; i < strArray.length; i++) {
            array[i] = Integer.valueOf(strArray[i]);
        }
        Arrays.sort(array);
        for (int i = 0; i < array.length; i++) {
            if (array[i] > 35) {
                length = i;
                break;
            }
        }
        int[] dest = new int[length];
        System.arraycopy(array, 0, dest, 0, length);
        return dest;
    }
}

此算法有做适当参考。

运行功效:

JAVA函数实现任意给定一组数, 找出任意数相加之后的功能为35

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