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C语言措施设计经典实例之十

2017-11-02 08:00 星期四 所属: C语言/C++ 教程 浏览:68

副标题#e#

【措施91】

题目:时间函数举例1

1.措施阐明:

2.措施源代码:

#include "stdio.h"
#include "time.h"
void main()
{
  time_t lt; /*define a longint time varible*/
  lt=time(NULL);/*system time and date*/
  printf(ctime(<)); /*english format output*/
  printf(asctime(localtime(<)));/*tranfer to tm*/
  printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/
}

【措施92】

题目:时间函数举例2

1.措施阐明:

2.措施源代码:

/*calculate time*/
#include "time.h"
#include "stdio.h"
main()
{
  time_t start,end;
  int i;
  start=time(NULL);
  for(i=0;i<3000;i++)
  {
   printf("\1\1\1\1\1\1\1\1\1\1\n");
  }
  end=time(NULL);
  printf("\1: The different is %6.3f\n",difftime(end,start));
}


#p#副标题#e#

【措施93】

题目:时间函数举例3

1.措施阐明:

2.措施源代码:

/*calculate time*/
#include "time.h"
#include "stdio.h"
main()
{
  clock_t start,end;
  int i;
  double var;
  start=clock();
  for(i=0;i<10000;i++)
  {
   printf("\1\1\1\1\1\1\1\1\1\1\n");
  }
  end=clock();
  printf("\1: The different is %6.3f\n",(double)(end-start));
}

【措施94】

题目:时间函数举例4,一个猜数游戏,判定一小我私家回响快慢。(版主初学时编的)

1.措施阐明:

2.措施源代码:

#include "time.h"
#include "stdlib.h"
#include "stdio.h"
main()
{
  char c;
  clock_t start,end;
  time_t a,b;
  double var;
  int i,guess;
  srand(time(NULL));
  printf("do you want to play it.('y' or 'n') \n");
  loop:
   while((c=getchar())=='y')
   {
    i=rand()%100;
    printf("\nplease input number you guess:\n");
    start=clock();
    a=time(NULL);
    scanf("%d",&guess);
    while(guess!=i)
    {
     if(guess>i)
     {
      printf("please input a little smaller.\n");
      scanf("%d",&guess);
     }
     else
     {
      printf("please input a little bigger.\n");
      scanf("%d",&guess);
     }
    }
    end=clock();
    b=time(NULL);
    printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);
    printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));
    if(var<15)
     printf("\1\1 You are very clever! \1\1\n\n");
    else if(var<25)
     printf("\1\1 you are normal! \1\1\n\n");
    else
     printf("\1\1 you are stupid! \1\1\n\n");
     printf("\1\1 Congradulations \1\1\n\n");
     printf("The number you guess is %d",i);
   }
   printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");
   if((c=getch())=='y')
    goto loop;
}

#p#副标题#e#

【措施95】

题目:家庭财政打点小措施

1.措施阐明:

2.措施源代码:

/*money management system*/
#include "stdio.h"
#include "dos.h"
main()
{
  FILE *fp;
  struct date d;
  float sum,chm=0.0;
  int len,i,j=0;
  int c;
  char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];
  pp: clrscr();
  sum=0.0;
  gotoxy(1,1);printf("|----------------------------------------------------|");
  gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |");
  gotoxy(1,3);printf("|----------------------------------------------------|");
  gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |");
  gotoxy(1,5);printf("| ------------------------ |-----------------------------|");
  gotoxy(1,6);printf("| date: -------------- | |");
  gotoxy(1,7);printf("| | | | |");
  gotoxy(1,8);printf("| -------------- | |");
  gotoxy(1,9);printf("| thgs: ------------------ | |");
  gotoxy(1,10);printf("| | | | |");
  gotoxy(1,11);printf("| ------------------ | |");
  gotoxy(1,12);printf("| cost: ---------- | |");
  gotoxy(1,13);printf("| | | | |");
  gotoxy(1,14);printf("| ---------- | |");
  gotoxy(1,15);printf("| | |");
  gotoxy(1,16);printf("| | |");
  gotoxy(1,17);printf("| | |");
  gotoxy(1,18);printf("| | |");
  gotoxy(1,19);printf("| | |");
  gotoxy(1,20);printf("| | |");
  gotoxy(1,21);printf("| | |");
  gotoxy(1,22);printf("| | |");
  gotoxy(1,23);printf("|--------------------------------------------------|");
  i=0;
  getdate(&d);
  sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);
  for(;;)
  {
   gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");
   gotoxy(13,10);printf(" ");
   gotoxy(13,13);printf(" ");
   gotoxy(13,7);printf("%s",chtime);
   j=18;
   ch[0 ]=getch();
   if(ch[0]==27)
    break;
    strcpy (chshop,"");
    strcpy(chmoney,"");
   if(ch[0]==9)
   {
    mm:i=0;
    fp=fopen("home.dat","r+");
    gotoxy(3,24);printf(" ");
    gotoxy(6,4);printf(" list records ");
    gotoxy(1,5);printf("|-------------------------------------|");
    gotoxy(41,4);printf(" ");
    gotoxy(41,5);printf(" |");
    while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!=EOF)
    {
     if(i==36)
     {
      getch();
      i=0;
     }
     if ((i%36)<17)
     {
      gotoxy(4,6+i);
      printf(" ");
      gotoxy(4,6+i);
     }
     else
     if((i%36)>16)
     {
      gotoxy(41,4+i-17);
      printf(" ");
      gotoxy(42,4+i-17);
     }
     i++;
     sum=sum+chm;
     printf("%10s %-14s %6.1f\n",chtime,chshop,chm);}
     gotoxy(1,23);printf("|----------------------------------------------|");
     gotoxy(1,24);printf("| |");
     gotoxy(1,25);printf("|----------------------------------------------|");
     gotoxy(10,24);printf("total is %8.1f$",sum);
     fclose(fp);
     gotoxy(49,24);printf("press any key to.....");getch();goto pp;
    }
    else
    {
     while(ch[0]!='\r')
     {
      if(j<10)
      {
       strncat(chtime,ch,1);
       j++;
      }
      if(ch[0]==8)
      {
       len=strlen(chtime)-1;
       if(j>15)
       {
        len=len+1;
        j=11;
       }
       strcpy(ch1,"");
       j=j-2;
       strncat(ch1,chtime,len);
       strcpy(chtime,"");
       strncat(chtime,ch1,len-1);
       gotoxy(13,7);printf(" ");
      }
      gotoxy(13,7);printf("%s",chtime);ch[0]=getch();
      if(ch[0]==9)
       goto mm;
      if(ch[0]==27)
       exit(1);
     }
     gotoxy(3,24);printf(" ");
     gotoxy(13,10);
     j=0;
     ch[0]=getch();
     while(ch[0]!='\r')
     {
      if (j<14)
      {
       strncat(chshop,ch,1);
       j++;
      }
      if(ch[0]==8)
      {
       len=strlen(chshop)-1;
       strcpy(ch1,"");
       j=j-2;
       strncat(ch1,chshop,len);
       strcpy(chshop,"");
       strncat(chshop,ch1,len-1);
       gotoxy(13,10);printf(" ");
      }
      gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}
      gotoxy(13,13);
      j=0; 
      ch[0]=getch();
      while(ch[0]!='\r')
      {
       if (j<6)
       {
        strncat(chmoney,ch,1);
        j++;
       }
       if(ch[0]==8)
       {
        len=strlen(chmoney)-1;
        strcpy(ch1,"");
        j=j-2;
        strncat(ch1,chmoney,len);
        strcpy(chmoney,"");
        strncat(chmoney,ch1,len-1);
        gotoxy(13,13);printf(" ");
       }
       gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();
      }
      if((strlen(chshop)==0)||(strlen(chmoney)==0))
       continue;
      if((fp=fopen("home.dat","a+"))!=NULL);
       fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);
       fputc('\n',fp);
       fclose(fp);
       i++;
       gotoxy(41,5+i);
       printf("%10s %-14s %-6s",chtime,chshop,chmoney);
     }
    }
  }

#p#副标题#e#

【措施96】

题目:计较字符串中子串呈现的次数

1.措施阐明:

2.措施源代码:

#p#分页标题#e#

#include "string.h"
#include "stdio.h"
main()
{
  char str1[20],str2[20],*p1,*p2;
  int sum=0;
  printf("please input two strings\n");
  scanf("%s%s",str1,str2);
  p1=str1;p2=str2;
  while(*p1!='\0')
  {
   if(*p1==*p2)
   {
    while(*p1==*p2&&*p2!='\0')
    {
     p1++;
     p2++;
    }
   }
   else
    p1++ ;
   if(*p2=='\0')
    sum++;
    p2=str2;
  }
  printf("%d",sum);
  getch();
}

【措施97】

题目:从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。

1.措施阐明:

2.措施源代码:

#p#分页标题#e#

#include "stdio.h"
main()
{
  FILE *fp;
  char ch,filename[10];
  scanf("%s",filename);
  if((fp=fopen(filename,"w"))==NULL)
  {
   printf("cannot open file\n");
   exit(0);
  }
  ch=getchar();
  ch=getchar();
  while(ch!='#')
  {
   fputc(ch,fp);putchar(ch);
   ch=getchar();
  }
  fclose(fp);
}

#p#副标题#e#

【措施98】

题目:从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中生存。输入的字符串以!竣事。

1.措施阐明:

2.措施源代码:

#include "stdio.h"
main()
{
  FILE *fp;
  char str[100],filename[10];
  int i=0;
  if((fp=fopen("test","w"))==NULL)
  {
   printf("cannot open the file\n");
   exit(0);
  }
  printf("please input a string:\n");
  gets(str);
  while(str[i]!='!')
  {
   if(str[i]>='a'&&str[i]<='z')
    str[i]=str[i]-32;
    fputc(str[i],fp);
   i++;
  }
  fclose(fp);
  fp=fopen("test","r");
  fgets(str,strlen(str)+1,fp);
  printf("%s\n",str);
  fclose(fp);
}

#p#副标题#e#

【措施99】

题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息归并(按字母顺序分列),
输出到一个新文件C中。

1.措施阐明:

2.措施源代码:

#include "stdio.h"
main()
{
  FILE *fp;
  int i,j,n,ni;
  char c[160],t,ch;
  if((fp=fopen("A","r"))==NULL)
  {
   printf("file A cannot be opened\n");
   exit(0);
  }
  printf("\n A contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {
   c[i]=ch;
   putchar(c[i]);
  }
  fclose(fp);
  ni=i;
  if((fp=fopen("B","r"))==NULL)
  {
   printf("file B cannot be opened\n");
   exit(0);
  }
  printf("\n B contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {
   c[i]=ch;
   putchar(c[i]);
  }
  fclose(fp);
  n=i;
  for(i=0;i<n;i++)
   for(j=i+1;j<n;j++)
    if(c[i]>c[j])
    {
     t=c[i];c[i]=c[j];c[j]=t;
    }
    printf("\n C file is:\n");
    fp=fopen("C","w");
    for(i=0;i<n;i++)
    {
     putc(c[i],fp);
     putchar(c[i]);
    }
    fclose(fp);
}

#p#副标题#e#

【措施100】

#p#分页标题#e#

题目:有五个学生,每个学生有3门课的后果,从键盘输入以上数据(包罗学生号,姓名,三门课后果),计较出平均后果,况原有的数据和计较出的平均分数存放在磁盘文件"stud"中。

1.措施阐明:

2.措施源代码:

#include "stdio.h"
struct student
{
  char num[6];
  char name[8];
  int score[3];
  float avr;
} stu[5];
main()
{
  int i,j,sum;
  FILE *fp;
  /*input*/
  for(i=0;i<5;i++)
  {
   printf("\n please input No. %d score:\n",i);
   printf("stuNo:");
   scanf("%s",stu[i].num);
   printf("name:");
   scanf("%s",stu[i].name);
   sum=0;
   for(j=0;j<3;j++)
   {
    printf("score %d.",j+1);
    scanf("%d",&stu[i].score[j]);
    sum+=stu[i].score[j];
   }
   stu[i].avr=sum/3.0;
  }
  fp=fopen("stud","w");
  for(i=0;i<5;i++)
  if(fwrite(&stu[i],sizeof(struct student),1,fp)!=1)
  printf("file write error\n");
  fclose(fp);
}

 

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