sys.argv[]是用来获取呼吁行参数的，sys.argv[0]暗示代码自己文件路径;好比在CMD呼吁行输入 “python test.py -help”，那么sys.argv[0]就代表“test.py”。
sys.startswith() 是用来判定一个工具是以什么开头的，好比在python呼吁行输入“'abc'.startswith('ab')”就会返回True
以下实例参考:
#!/usr/local/bin/env python
import sys
def readfile(filename):
'''Print a file to the standard output.'''
f = file(filename)
while True:
line = f.readline()
if len(line) == 0:
break
print line,
f.close()
print "sys.argv[0]---------",sys.argv[0]
print "sys.argv[1]---------",sys.argv[1]
print "sys.argv[2]---------",sys.argv[2]
# Script starts from here
if len(sys.argv) < 2:
print 'No action specified.'
sys.exit()
if sys.argv[1].startswith('--'):
option = sys.argv[1][2:]
# fetch sys.argv[1] but without the first two characters
if option == 'version':
print 'Version 1.2'
elif option == 'help':
print '''"
This program prints files to the standard output.
Any number of files can be specified.
Options include:
--version : Prints the version number
--help : Display this help'''
else:
print 'Unknown option.'
sys.exit()
else:
for filename in sys.argv[1:]:
readfile(filename)
执行功效:# python test.py --version help
sys.argv[0]--------- test.py
sys.argv[1]--------- --version
sys.argv[2]--------- help
Version 1.2
留意:sys.argv[1][2:]暗示从第二个参数，从第三个字符开始截取到最后末了，本例功效为:version
