Chem 1220 Midterm 2
化学考试代写 1.If 1.00 mole of HF(g), 0.500 mole of H2(g), and 0.750 mol of F2(g) are mixed in a 5.00 L flask, what is the reaction quotient and
1.
If 1.00 mole of HF(g), 0.500 mole of H2(g), and 0.750 mol of F2(g) are mixed in a 5.00 L flask, what is the reaction quotient and the net direction to reach equilibrium
H2(g) + F2(g) ⇌ 2 HF(g) Kc = 100
(a) Q = 2.66, the system is at equilibrium
(b) Q = 0.375, the equilibrium shifts to the right
(c) Q = 2.66, the equilibrium shifts to the left
(d) Q = 0.375, the equilibrium shifts to the left
(e) Q = 2.66, the equilibrium shifts to the right
2.
Given the following equilibrium
CO(g) + 2 H2(g) ⇌ CH3OH(g)
A chemist introduces 0.42 mol of CO and 0.42 mol of H2 into a 1.00 L reaction vessel. Once the mixture comes to equilibrium there are 0.29 mol of CO remaining. What is the equilibrium constant, Kc at this temperature?
(a) 2.80
(b) 0.357
(c) 14.5
(d) 17.5
(e) None of the above
3.
The reaction
PCl5(g) ⇌ PCl3(g) + Cl2(g) ΔH° = 88 kJ
Is at equilibrium. Which of the following changes will shift the equilibrium to the right?
(1) removing Cl2
(2) decreasing the temperature
(3) increasing the volume of the reaction vessel
(a) 1 only
(b) 2 only
(c) 3 only
(d) 1 and 3
(e) 1 and 2
4. 化学考试代写
Consider the following molecules CH3NH2, CH3CH2OH, CH3CH2CO2H. Amongst these three _______ is a weak acid, _______ is a weak base, and _______ is neither an acid nor a base in aqueous solution.
(a) CH3CH2CO2H, CH3NH2 , CH3CH2OH
(b) CH3CH2CO2H, CH3CH2OH, CH3NH2
(c) CH3NH2 , CH3CH2OH, CH3CH2CO2H
(d) CH3CH2OH, CH3NH2 , CH3CH2CO2H
(e) CH3NH2 , CH3CH2CO2H, CH3CH2OH
5.
Given the following Ka values determine which species is the strongest base
HF, Ka = 6.8 × 10–4 HNO2, Ka = 4.5 × 10–4 HCNO, Ka= 2.2 × 10–4
(a) F–
(b) NO2–
(c) CNO–
(d) HF
(e) HCNO
6.
If 0.500 mol of H2(g) and 0.500 mol of I2(g) are placed in a 2.00 L container at a temperature where the following equilibrium exists:
H2(g) + I2(g) ⇌ 2 HI(g) Kc = 125
What concentration of HI(g) is present once the system comes to equilibrium?
(a) 0.424 M
(b) 0.0405 M
(c) 0.380 M
(d) 0.230 M
(e) 0.212 M
7.
What is the % ionization of a 0.015 M solution of hypochlorous acid, HClO (Ka = 3.0 × 10-8 )?
(a) 2.1 × 10-5 %
(b) 0.0014 %
(c) 0.14 %
(d) 1.5 %
(e) 14 %
8. 化学考试代写
What is the pH of a 0.050 M solution of H2SO4 (Ka2 = 0.012)?
(a) 1.01
(b) 1.23
(c) 1.30
(d) 1.28
(e) 2.07
9.
Arrange the following molecules/ions from the weakest to strongest base: Cl– , OH– , O2–, NH3 .
(a) Weakest base Cl– < NH3 < O2– < OH– Strongest base
(b) Weakest base O2– < Cl– < NH3< OH– Strongest base
(c) Weakest base Cl– < NH3 < OH– < O2– Strongest base
(d) Weakest base Cl– < O2–< NH3 < OH– Strongest base
(e) Weakest base NH3 < Cl– < OH– < O2– Strongest base
10.
An solution of Ca(OH)2 is determined to have a pH of 11.24. What is the concentration of Ca(OH)2 in this solution?
(a) 5.75 × 10-11 M
(b) 1.74 × 10-3 M
(c) 8.69 × 10-4 M
(d) 3.47 × 10-3 M
(e) 2.76 × 10-1 M
11.
Both bromous acid (HBrO2) and hypobromous acid (HBrO) are weak acids. In both molecules the hydrogen atom is bound to _______ , yet the bond is more polar in ______ which makes it a stronger acid (larger Ka).
(a) bromine, HBrO
(b) bromine, HBrO2
(c) oxygen, HBrO
(d) oxygen, HBrO2
12. 化学考试代写
What is the pH of a 0.50 M solution of NaBrO? The Ka of HBrO is 2.5 × 10-9 .
(a) 2.85
(b) 3.20
(c) 9.67
(d) 10.80
(e) 11.15
13.
How many of the following salts will form acidic solutions when dissolved in water?
AlCl3 NaBr NaClO Na2SO3 CH3NH3NO3
(a) 0
(b) 1
(c) 2
(d) 3
14.
A buffer is prepared by adding 10.0 g of NH4Cl (molar mass = 53.5 g/mol) to 250.0 mL of 1.00 M NH3 (Kb = 1.8 × 10-5 ) solution. What is the pH of this buffer? Ignore any changes in volume that occur on mixing.
(a) 10.14
(b) 9.98
(c) 9.38
(d) 9.13
(e) 4.87
15. 化学考试代写
If 8.00 mL of 2.00 M HNO3(aq) solution are added to the buffer from the previous problem what is the new pH?
(a) 10.01
(b) 9.44
(c) 9.31
(d) 4.93
(e) 4.81
Physical Constants
R = 8.314 J∙mol-1∙K-1
R = 0.0821 L∙atm∙mol-1 ∙K-1
1 F = 96,500 C∙mol-1
1 F = 96,500 J∙V-1∙mol-1
NA = 6.022 x 1023 mol-1
h = 6.626 x 10-34 J∙s
c = 2.998 x 108 m∙s-1
0° C = 273.15 K
KW = 1.00 x 10-14 at 25° C
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